let nbe the first multiple of 3, the consecutive multiple is X+3
5x (n+3)>/=2n+45
5n+15 is more than orequal to 2n+45
3n+15 >/=45
3n>/=45-15
n=10 (agree with you up to this part)
n is a multiple of 3 but 10 is not, so the smallest possible number (LCM)is 30
the larger possible number is 30+3=33
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